Friday, 19 April 2013

print one part in form asp.net

No print preview, but this will print only the specified <div> tag:

<form id="Form1" method="post" runat="server">
<div id="Div1">
Printable content
</div>
<input type="button" value="Print" onclick="JavaScript:printPartOfPage('Div1');">

<script type="text/javascript">

</script>

</form>

Asp.net TextBox watermark in JQuery

This short article demonstrates how to create a watermark effect on your TextBox and display instructions to users, without taking up screen space. This article is a sample chapter from my EBook called 51 Tips, Tricks and Recipes with jQuery and ASP.NET Controls. The chapter has been modified a little to publish it as an article.
Note that for demonstration purposes, I have included jQuery code in the same page. Ideally, these resources should be created in separate folders for maintainability.
Let us quickly jump to the solution and see how we can create a watermark effect on your TextBox using client-side code.
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">

<html xmlns="http://www.w3.org/1999/xhtml">
<head id="Head1" runat="server">
<title>TextBox WaterMark</title>
<script type="text/javascript"
src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.min.js">
</script>

<style type="text/css">
.water
{
font-family: Tahoma, Arial, sans-serif;
color:gray;
}
</style>

<script type="text/javascript">
$(function() {

$(".water").each(function() {
$tb = $(this);
if ($tb.val() != this.title) {
$tb.removeClass("water");
}
});

$(".water").focus(function() {
$tb = $(this);
if ($tb.val() == this.title) {
$tb.val("");
$tb.removeClass("water");
}
});

$(".water").blur(function() {
$tb = $(this);
if ($.trim($tb.val()) == "") {
$tb.val(this.title);
$tb.addClass("water");
}
});
});

</script>
</head>
<body>
<form id="form1" runat="server">
<div class="smallDiv">
<h2>TextBox Watermark Demonstration</h2> <br />
<asp:TextBox ID="txtFNm" class="water" Text="Type your First Name"
Tooltip="Type your First Name" runat="server"></asp:TextBox><br />
<asp:TextBox ID="txtLNm" class="water" Text="Type your Last Name"
Tooltip="Type your Last Name" runat="server"></asp:TextBox>
<br /><br />
<asp:Button ID="btnSubmit" runat="server" Text="Submit" />
<br /><br />
Tip: Click on the TextBox to start typing. The watermark
text disappears.
</div>
</form>
</body>
</html>

Nested grid view example

write below code to the NetedGrid.aspx page

<asp:GridView ID="gvParent" runat="server" AutoGenerateColumns="False"
BackColor="White" BorderColor="White" BorderStyle="Ridge" BorderWidth="2px"
CellPadding="3" CellSpacing="1" GridLines="None"
onrowcommand="gvParent_RowCommand">
<Columns>
<asp:BoundField DataField="Grp_Id" HeaderText="ID" SortExpression="Grp_Id" />
<asp:BoundField DataField="GrpNm" HeaderText="Name" SortExpression="GrpNm" />
<asp:TemplateField HeaderText="Group">
<ItemTemplate>
<asp:Button ID="btnShowChild" runat="server"
CommandArgument='<%# Bind("Grp_Id") %>' CommandName="ShowChild" Text="+" />
<asp:Button ID="btnHideChild" runat="server"
CommandArgument='<%# Bind("Grp_Id") %>' CommandName="HideChild" Text="-" Visible="false" />
<asp:GridView ID="gvChild" runat="server" AutoGenerateColumns="False">
<Columns>
<asp:BoundField DataField="Acct_Id" HeaderText="AcctId"
SortExpression="Acct_Id" />
<asp:BoundField DataField="PartyNm" HeaderText="Party Name"
SortExpression="PartyNm" />
<asp:BoundField DataField="TempAdd" HeaderText="Address"
SortExpression="TempAdd" />
</Columns>
</asp:GridView>
</ItemTemplate>
</asp:TemplateField>
</Columns>
<FooterStyle BackColor="#C6C3C6" ForeColor="Black" />
<HeaderStyle BackColor="#4A3C8C" Font-Bold="True" ForeColor="#E7E7FF" />
<PagerStyle BackColor="#C6C3C6" ForeColor="Black" HorizontalAlign="Right" />
<RowStyle BackColor="#DEDFDE" ForeColor="Black" />
<SelectedRowStyle BackColor="#9471DE" Font-Bold="True" ForeColor="White" />
</asp:GridView>

code for NestedGrid.aspx.cs file

using System;
using System.Configuration;
using System.Data;
using System.Data.SqlClient;
using System.Linq;
using System.Web;
using System.Web.Security;
using System.Web.UI;
using System.Web.UI.HtmlControls;
using System.Web.UI.WebControls;
using System.Web.UI.WebControls.WebParts;
using System.Xml.Linq;

public partial class NestedGrid : System.Web.UI.Page
{
SqlConnection con = new SqlConnection(ConfigurationManager.ConnectionStrings["adv"].ConnectionString);
string query = null;
protected void Page_Load(object sender, EventArgs e)
{
if (!IsPostBack)
{
BindParentGrid();
}
}
public void BindParentGrid()
{
query = "SELECT [Grp_Id] ,[GrpNm] FROM [dbo].[tbl_Group]";
SqlDataAdapter sdap = new SqlDataAdapter(query, con);
DataSet ds = new DataSet();
sdap.Fill(ds);
gvParent.DataSource = ds;
gvParent.DataBind();
ds.Clear();
}
protected void gvParent_RowCommand(object sender, GridViewCommandEventArgs e)
{
if (e.CommandName== "ShowChild")
{
query = "SELECT * FROM [dbo].[tbl_AccountMaster] where [Grp_Id]="+e.CommandArgument.ToString()+"";
SqlDataAdapter sdap = new SqlDataAdapter(query, con);
DataSet ds = new DataSet();
sdap.Fill(ds);
for (int i = 0; i < gvParent.Rows.Count; i++)
{
if (e.CommandArgument.ToString() == (gvParent.Rows[i].Cells[0].Text))
{
((GridView)gvParent.Rows[i].FindControl("gvChild")).DataSource = ds;
((GridView)gvParent.Rows[i].FindControl("gvChild")).DataBind();
((Button)gvParent.Rows[i].FindControl("btnShowChild")).Visible = false;
((Button)gvParent.Rows[i].FindControl("btnHideChild")).Visible = true;
}
}
}
if (e.CommandName == "HideChild")
{

for (int i = 0; i < gvParent.Rows.Count; i++)
{
if (e.CommandArgument.ToString() == (gvParent.Rows[i].Cells[0].Text))
{
((GridView)gvParent.Rows[i].FindControl("gvChild")).DataSource = null;
((GridView)gvParent.Rows[i].FindControl("gvChild")).DataBind();
((Button)gvParent.Rows[i].FindControl("btnShowChild")).Visible = true;
((Button)gvParent.Rows[i].FindControl("btnHideChild")).Visible = false;
}
}
}
}
}

Monday, 15 April 2013

Validation of viewstate mac failed

Per my finding issue cause due to "EnableViewStateMac" property is by default true . we need to false "EnableViewStateMac" property in web.config file.
I have made below changes under web.config file and its working fine.
web.config change:-
<asp:Page EnableViewStateMac="False" />

Thursday, 11 April 2013

login/logout issue for multiple IIS applications under the same site

If the IIS website is configured to use Forms-Based Authentication, then the problem is most likely that the cookie for the 2nd login (which is a different user) is overwriting the cookie from the initial login.

By default, the cookie is named ".ASPXAUTH".

You can control the cookie name IIS uses to maintain the session by changing the "name" attribute in the element in the web.config. An example of this portion of the web.config would be something like:

<authentication mode="Forms">

<forms loginUrl="login.aspx" name="APP1SESS" />

Swapnil Mahangare